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Question

A solution which is 103M each in Mn2+,Fe2+ and Hg2+ is treated with 1016 M sulphide ion, If Ksp of  MnS,FeS,ZnS and HgS are 1015,1025,1020 and 1054 respectively, which one will precipitate first?


Your Answer
A
FeS
Your Answer
B
MnS
Correct Answer
C
HgS
Your Answer
D
ZnS

Solution

The correct option is C HgS
Ionic product of the solution =103×1016=1019.
The metal sulphide having the lowest solubility will precipitate first provided the ionic product is higher than the Ksp.
Here, all salts are of the same valence type. So, the sulphide having the lowest Ksp value will precipitate first provided Ksp1019.
HgS has the lowest Ksp value (1054) so it will precipitate first.

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