A solution of 0-1 N N H 4 OH and 0-1 N N H 4 Cl has pH 9-25 - Then pK b of NH 4 OH isA- 9-25B- 4-75C- 3-75D- 8-25

The correct option is B 4.75pOH=pK_b +log [salt]/Base [Salt] = [Base] ∴ pOH = pK_b pOH = 14 –pH = 14 – 9.25 = 4.75 ...

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A solution of $0.1 N N H_{4} O H$ and $0.1 N N H_{4} C l$ has pH 9.25. Then $p K_{b}$ of $N H_{4} O H$ is

9.25

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4.75

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3.75

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8.25

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