A solution of 1.25g of non - electrolyte in 20g of water freezes at 271.94 K. If K_f = 1.86 K kg mol^-1, then the molecular weight of the solute will be:

179.79g mol^-1

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207.8 g mol^-1

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209.6 g mol^-1

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109.6 g/ mol^-1

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Solution

The correct option is D
109.6 g/ mol^-1

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A solution of 1.25g of non - electrolyte in 20g of water freezes at 271.94 K. If K_f = 1.86 K kg mol^-1,then the molecular weight of the solute will be:

Q. A solution of 1.25 g of a non - electrolyte in 20 g of water freezes at 271.94 K. If

K_{f}

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C_{2} H_{5} O H

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? [Mol. wt. of

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for water

= 1.86 K k g m o l^{- 1}

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Q. The freezing point of a 0.05 molal solution of non-electrolyte in water is:

[K_{f} = 1.86 K m^{- 1}]

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A solution of 1.25g of non - electrolyte in 20g of water freezes at 271.94 K. If Kf = 1.86 K kg mol-1, then the molecular weight of the solute will be:

The correct option is D109.6 g/ mol-1

A solution of 1.25g of non - electrolyte in 20g of water freezes at 271.94 K. If K_f = 1.86 K kg mol^-1, then the molecular weight of the solute will be:

The correct option is D
109.6 g/ mol^-1