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Standard X

Chemistry

Mole Concept

A solution of...

Question

A solution of 200 mL of 1 $M$ KOH is added to 200 mL of 1 $M$ HCl and the mixture is well shaken. This rise in temperature $T_{1}$ is noted. The experiment is repeated by using 100 mL of each solution and increase in temperature $T_{2}$ is again noted. Which of the following is correct?

T_{1} = T_{2}

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T_{2}

is twice as large as

T_{1}

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T_{1}

is twice as large as

T_{2}

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T_{1}

is four times as large as

T_{2}

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Solution

The correct option is C $T_{1} = T_{2}$
Heat produced by 200 Meq of $K O H + H C l$ $= \frac{13.7 \times 200}{1000} k c a l$
This is used to raise the temperature of 400 mL solution say by $T_{1}$ .
Thus, $= \frac{13.7 \times 200}{1000} = 400 \times S \times T_{1}$
Now, heat produced by 100 Meq of $K O H + H C l$ $= \frac{13.7 \times 100}{1000}$
Thus, $\frac{13.7 \times 100}{1000} = 200 \times S \times T_{2}$
It is evident that $T_{1} = T_{2}$ .

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Similar questions

Q. A solution of 200 ml of 1M KOH is added to 200 ml of 1M HCl and the mixture is shaken well. The rise in temperature

T_{1}

is noted. The experiment is repeated by using 100 ml each solution and increase in temperature

T_{2}

is again noted. Which of the following is correct ?

Q. A solution is 500 mL of 2 M

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is added to 500 mL of 2 M

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and the mixture is well shaken. The rise in temperature

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Q. A solution is 500 mL of 2 M KOH is added to 500 mL of 2 M HCl and the mixture is well shaken. The rise in temperature

T_{1}

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T_{2}

is again noted. Assume all heat is taken by the solution

500

mL of

0.2

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500

mL of

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M HCl and the mixture is well shaken. The rise in temperature

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A solution of 200 mL of 1 M KOH is added to 200 mL of 1 M HCl and the mixture is well shaken. This rise in temperature T1 is noted. The experiment is repeated by using 100 mL of each solution and increase in temperature T2 is again noted. Which of the following is correct?

The correct option is C T1=T2Heat produced by 200 Meq of KOH+HCl=13.7×2001000kcalThis is used to raise the temperature of 400 mL solution say by T1.Thus, =13.7×2001000=400×S×T1Now, heat produced by 100 Meq of KOH+HCl=13.7×1001000Thus, 13.7×1001000=200×S×T2It is evident that T1=T2.

A solution of 200 mL of 1 $M$ KOH is added to 200 mL of 1 $M$ HCl and the mixture is well shaken. This rise in temperature $T_{1}$ is noted. The experiment is repeated by using 100 mL of each solution and increase in temperature $T_{2}$ is again noted. Which of the following is correct?