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Question

A solution of 200 mL of 1 M KOH is added to 200 mL of 1 M HCl and the mixture is well shaken. This rise in temperature T1 is noted. The experiment is repeated by using 100 mL of each solution and increase in temperature T2 is again noted. Which of the following is correct?

A
T1=T2
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B
T2 is twice as large as T1
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C
T1 is twice as large as T2
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D
T1 is four times as large as T2
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Solution

The correct option is C T1=T2
Heat produced by 200 Meq of KOH+HCl=13.7×2001000kcal
This is used to raise the temperature of 400 mL solution say by T1.
Thus, =13.7×2001000=400×S×T1
Now, heat produced by 100 Meq of KOH+HCl=13.7×1001000
Thus, 13.7×1001000=200×S×T2
It is evident that T1=T2.

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