A solution of (Al2(SO4)3) contain 22% salt by weight and density of solution is 1.253 g/mL. The molarity, normality and molality of the solution are:
Molecular wt. of Al2(SO4)3=2×27+3×(32+4×16) =342 g/mole
Equivalent wt. of Al2(SO4)3=Eq.wt.of Al3++ Eq.Wt of SO2−4=273+962
=57g eq
No. of. equivalent per mole =34257=6
Let volume of solutions = 1 L
Wt. of solutions = V× density =1000×1.253=1253 g
Wt. of solute = 1253× 22%=257.66
Moles. of solute = 275.66342=0.806
Wt. of solvent = 1253−257.66=977.34
Molarity = moles of soluteVolume of solution=0.806 M
Normality = 6× Molality =6× 0.806= 4.836 N
Molalit = Moles of solute Wt.of solvent in k.g=0.806977.34/1000=0.825 m