A solution of glucose ( $C_{6} H_{12} O_{6}$ ) is isotonic with 4 g of urea $(H_{2} N - C O - N H_{2})$ per litre of solution. The concentration of glucose is:

4 g / L

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3 g / L

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12 g / L

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14 g / L

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Solution

The correct option is C $12 g / L$
Isotonic solutions are those that have the same osmotic pressure.
Osmotic pressure, $π = C R T$
So here, both the solutions should have the same concentration.
Let, $x$ gm of glucose present in 1 litre solution.
So, according to the question,
$\frac{x}{180} = \frac{4}{60}$
$⟹ x = 12 g / L$

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