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Question

At a constant temperature, a solution of glucose (C6H12O6) is isotonic with 4 g of urea (NH2−CO−NH2) per liter of solution. The concentration of glucose is

A
4 g/L
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B
8 g/L
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C
12 g/L
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D
14 g/L
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Solution

The correct option is C 12 g/LOsmotic preaaure, π=CRT Here C is concentration in molarity. R is universal gas constant and T is temperature. C=nV n=Given massMolar mass Given mass of urea=4 g Volume of each solution =1 L Since both solutions have same osmotic pressure, they have same concentrations also. Let, the mass of glucose be X g per liter solution. ∴ C1=C2 ⇒n1V=n2V⇒460=X180 ⇒X=12 g/L

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