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Question

A solution of H3PO4(d=1.8 g/ml) has a molarity of 18 M. Hence, mass percentage and molality are:

A
18%, 32.4 molal
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B
98%, 32.4 molal
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C
98%, 500 molal
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D
98%, 18 molal
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Solution

The correct option is C 98%, 500 molal
18 M H3PO4=18 mol H3PO4 in 1000 ml solution

Given, density of the solution d=1.8 g/ml

So mass of 1000 ml solution 1.8×1000=1800 g
Mass of 18 mol H3PO4=18×98=1764 g

So mass percentage of H3PO4=17641800×100=98%

Molality=1836×1000=500 m

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