A solution of sulphur dioxide in water reacts with $H_{2} S$ precipitating sulphur. Here sulphur dioxide acts as

As oxidising agent

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A reducing agent

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An acid

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A catalyst

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Solution

The correct option is A As oxidising agent
When sulphur dioxide reacts with $H_{2} S$ , $S O_{2}$ acts as an oxidising agent (gets reduced itself) and $H_{2} S$ acts as a reducing agent (gets oxidised).

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S O_{2}

H_{2} S

S O_{2}

H_{2} S

S O_{2}

H_{2} S

S O_{2}

In the reaction $2 A g + 2 H_{2} S O_{4} \to A g_{2} S O_{4} + 2 H_{2} O + S O_{2}$ sulphuric acid acts as

_{2}

_{2}

_{2}

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