A solution which is 10^-3 M each in Mn²⁺, Fe²⁺, Zn²⁺ and Hg²⁺ is treated with 10^-16 M sulphide ion. If K_sp of MnS, FeS, ZnS and HgS are 10^-15, 10^-23, 10^-20 and 10^-54 respectively, which one will precipitate first?

A solution which has $10^{- 3}$ M each of $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ and $H g^{2 +}$ is treated with $10^{- 16}$ M sulphide ion. If $K_{s p}$ of $M n S$ , $F e S$ , $Z n S$ and $H g S$ are $10^{- 15}$ , $10^{- 23}$ , $10^{- 20}$ and $10^{- 54}$ respectively, which one will precipitate first?

Join BYJU'S Learning Program

A solution which is 10−3M each in Mn2+,Fe2+,Zn2+ and Hg2+ is treated with 10−16M sulphide ion. If Ksp of MnS,FeS,ZnS andHgS are 10−15,10−23,10−20 and 10−54respectively, which one will precipitate first?

The correct option is C HgSSalt having low Ksp precipitates first.Thus HgS will precipitate first.

A solution which is $10^{- 3} M$ each in $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ and $H g^{2 +}$ is treated with $10^{- 16} M$ sulphide ion. If $K_{s p}$ of MnS,FeS,ZnS andHgS are $10^{- 15}, 10^{- 23}, 10^{- 20}$ and $10^{- 54}$ respectively, which one will precipitate first?

The correct option is C HgS
Salt having low $K_{s p}$ precipitates first.
Thus $H g S$ will precipitate first.