CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A sound wave of wavelength 40 cm travels in air. If the difference between maximum and minimum pressures at a given point is 1.0×103 N/m2, then find the amplitude of vibrations of the particles of the medium.
[Bulk modulus of air is 1.4×105 N/m2]

A
3.3×1010 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.3×1010 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4.3×1010 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5.3×1010 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2.3×1010 m
Let P be the atmospheric pressure.
Difference between maximum and minimum pressures at a given point,
[(P+Po)(PPo)]=1.0×103 N/m2
2Po=1.0×103 N/m2
Po=0.5×103 N/m2
We know the relation between maximum value of pressure in the medium and displacement of the particles in the medium is given by,
Po=BAok
Ao=PoBk=λPo2πB
Ao=40×102×0.5×1032×3.14×1.4×105
Ao=2.3×1010 m

flag
Suggest Corrections
thumbs-up
10
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon