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Intensity of Sound Waves

A source and ...

Question

A source and an observer move away from each other with speed of $10 m / s$ with respect to ground. Apparent frequency of the source is $1950 H z$ . The natural frequency of the source is (velocity of sound is $340 m / s$ )

A

2068 H z

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B

1832 H z

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C

1950 H z

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D

1650 H z

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Solution

The correct option is D $2068 H z$
Given :
$ϑ_{0} = 10 m / s$
$V_{s} = - 10 m / s$
$δ = 1950 H z$
$V = 340 m / s$
By doppler effect formula:
$δ^{1} = δ (\frac{V - V_{0}}{V - V_{s}})$
$1950 = δ (\frac{340 - 10}{340 + 10})$
$δ = \frac{1950 \times 350}{330}$ $= 2068 H z$

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