A source and listener are both moving towards each other with speed v10 where v is the speed of sound. If the frequency of the note emitted by the source is f, the frequency heard by the listener would be nearly
A
0.75 f
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B
1.22 f
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C
f
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D
2f
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Solution
The correct option is B1.22 f n′=(v+vLv−vs)n⇒n′=(v+v10v−v10)n⇒n′=119f=1.22f