A source emitting sound at frequency 4000 Hz, is moving along the Y-axis with a speed of $22 m s^{- 1}$ . A listener is situated on the ground at the position (660 m, 0). Find the frequency of the sound received by the listener at the instant the source crosses the origin. Speed of sound in air $= 330 m s^{- 1}$ .

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Solution

Required frequency

$= \frac{v + 0}{v - v_{s} c o s θ} \times n_{0}$

$= \frac{330}{330 - 22 \times \frac{44.09}{661.47}} \times 4000$

$= 4017.85 \approx 4018 H z$

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Required frequency =v+0v−vs cos θ×n0 =330330−22×44.09661.47×4000 =4017.85≈4018Hz

Required frequency

$= \frac{v + 0}{v - v_{s} c o s θ} \times n_{0}$

$= \frac{330}{330 - 22 \times \frac{44.09}{661.47}} \times 4000$

$= 4017.85 \approx 4018 H z$