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Ohm's Law

A source of c...

Question

A source of constant potential difference is connected across a conductor having irregular cross-section as shown in figure. Then :-

Electric field intensity at

P

is greater than at

Q .

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Rate of electric current crossing per unit area of cross section at P is less than that at

Q

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The rate of generation of heat per unit length at

P

is greater than that at

Q

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Mean kinetic energy of free electron at

P

is greater than that at

Q

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Solution

The correct option is B Rate of electric current crossing per unit area of cross section at P is less than that at $Q$ .
For a conductor with constant applied potential difference, $J A = I$ is constant across any cross section.
At $P$ , is larger than that at $Q$ , hence $J$ is less at $P$ than at $Q$ .
Therefore, rate of current crossing per unit area is less at $P$ than $Q$ .

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Similar questions

A

B

A

B

Table 1	Table 2
(a) current at A	(p) is zero
(b) drift velocity of electrons at A	(q) is more than at B
(c) electric field in the wire at A	(r) is less than at B
(d) current density at A	(s) is equal to that at B

i

$(a)$ Current density	$(p)$ is more at $1$
$(b)$ Electric field	$(q)$ is more at $2$
$(c)$ Resistance per unit length	$(r)$ is same at both sections $1$ and $2$
$(d)$ Potential difference per unit length	$(s)$ Data insufficient

I = n e A V_{d}

V_{d}

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