The correct option is
D Let
f0 be the frequency of sound heard by the observer, when both source of sound and observer are at rest and
v be the velocity of sound in the stationary medium.
When a source moves towards the observer :
The frequency heard by the stationary observer
fapp=(vv−vs)f0
Since,
v−vs<v , we can conclude that,
fapp>f0
Hence, when the source moves towards the stationary observer, there is no decrease in the frequency of sound.
So, options (a) and (b) are wrong.
When a source moves away from the observer :
The frequency heard by the stationary observer
fapp=(vv+vs)f0
Since,
v+vs>v , we can conclude that,
fapp<f0
Hence, when the source moves away from the stationary observer, there is a decrease in the frequency of sound.
Decrement is greater when
vs is greater.
Thus, option (d) is the correct answer.