A source of sound with adjustable frequency produces 2 beats per second with a tuning fork, when its frequency is either 466Hz or 470Hz. What is the frequency of the tuning fork ?
A
466Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
470Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
468Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
472Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C468Hz Let f be the freqency of the tuning fork.
The frequency of sound source for which 2 beats per second have been observed are, f1=466Hz & f2=470Hz
Therefore, |f−f1|=2 ⇒f−466=±2 ⇒f=468Hzor464Hz
Similarly, |f−f2|=2 ⇒f−470=±2 ⇒f=472Hzor468Hz
Since the same tuning fork has been used each time, hence on comparing ′f′ we get: ⇒f=468Hz