Question

A spanner of length 10 cm is used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.

Answer 1

⊥ Distance = 10cm = $\frac{10}{100}$ m

= $\frac{1}{10}$ m

Force applied on spanner 5 N
∴ Moment of force = $Force\times$ $\perp distance$
= $5\times$ $\frac{1}{10}$

= 0.5 N m