A spanner opens a bolt by applying a force of $100 N$ Length of spanner is $10 c m$ . If force is reduced to $50 N$ , what should be the length of spanner?

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Solution

The torque is given as,

$τ = F \times l$

By equating the torques on both sides, we get

$F_{1} \times l_{1} = F_{2} \times l_{2}$

$100 \times 10 = 50 \times l_{2}$

$l_{2} = 20 c m$

Thus, the length of the spanner is $20 c m$ .

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A spanner opens a bolt by applying a force of 100N Length of spanner is 10cm . If force is reduced to 50N , what should be the length of spanner?

The torque is given as, τ=F×l By equating the torques on both sides, we get F1×l1=F2×l2 100×10=50×l2 l2=20cm Thus, the length of the spanner is 20cm.

A spanner opens a bolt by applying a force of $100 N$ Length of spanner is $10 c m$ . If force is reduced to $50 N$ , what should be the length of spanner?

The torque is given as,

$τ = F \times l$

By equating the torques on both sides, we get

$F_{1} \times l_{1} = F_{2} \times l_{2}$

$100 \times 10 = 50 \times l_{2}$

$l_{2} = 20 c m$

Thus, the length of the spanner is $20 c m$ .