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Question

A sphere of radius 1cm has potential of 8000V, then energy density near its surface will be____( in MKS )

A
31.87
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B
63.43
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C
8.52
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D
2.83
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Solution

The correct option is C 2.83
Given,
R=1cm=0.01m
V=8000V
Electric field is given by
E=VR=80000.01=8×105V/m
The energy density near a surface of sphere,
U=12ε0E2
U=12×8.85×1012×8×8×1010
U=2.83J/kgs
The correct option is D.

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