A spherical mirror forms an image of magnification 3. The object distance, if focal length of mirror is 24 cm, may be

32 cm, 24 cm

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32 cm, 16 cm

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32 cm only

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16 cm only

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Solution

The correct option is D 16 cm only
Since the magnification is positive, the image is clearly virtual and erect.

Case I (Convex mirror)

Case II (Concave mirror)

Since magnification $> 1$ , the image should be enlarged. Therefore, only case II can be correct.

To obtain virtual image with a concave mirror, object distance must be less than focal length (i.e $24 c m$ ). Therefore only option d matches.

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Similar questions

In order to obtain a magnification of, -1.5 with a concave mirror of focal length 16 cm, the object will have to be placed at a distance : (a) between 6 cm and 16 cm ,(b) between 32 cm and 16 cm (c) between 48 cm and 32 cm (d) beyond 64 cm

Q. A spherical mirror forms an image of magnification

3

for a real object. If the focal length of the mirror is

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, then the object distance may be

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5

times greater than the object. If the radius of curvature is

40 c m

, determine the distance of the object from the mirror?

Q. A spherical mirror forms an image of size

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Q. A

2 c m

high object is placed at a distance of

32 c m

from a concave mirror. The image is real inverted and

3 c m

in size. Find the focal length of the mirror and the position where the image is formed.

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