A spherical shell is cut into two pieces along a chord and separated by a large distance as shown in figure- For points A and B- where V and E are gravitational potential and field respectively- thenA- V A - V B and - E A - E B -B- V A - V B and - E A - E B -C- V A - V B and - E A - E B -D- V A - V B and - E A - E B -

The correct option is D V_A lt; V_B and nbsp; |E_A| = |E_B|Since the net gravitational field inside a spherical shell is zero E_A + E_B = 0 |E_A| = |E_B ...

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Standard XII

Physics

Gravitational Field

A spherical s...

Question

A spherical shell is cut into two pieces along a chord and separated by a large distance as shown in figure. For points $A$ and $B$ , where $V$ and $\to E$ are gravitational potential and field respectively, then

V_{A} = V_{B} and | {\to E}_{A} | > | {\to E}_{B} |

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V_{A} < V_{B} and | {\to E}_{A} | = | {\to E}_{B} |

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V_{A} = V_{B} and | {\to E}_{A} | = | {\to E}_{B} |

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V_{A} > V_{B} and | {\to E}_{A} | < | {\to E}_{B} |

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Solution

The correct option is B $V_{A} < V_{B} and | {\to E}_{A} | = | {\to E}_{B} |$
Since the net gravitational field inside a spherical shell is zero
${\to E}_{A} + {\to E}_{B} = 0$
$| {\to E}_{A} | = | {\to E}_{B} |$
Analyzing gravitational field lines, $V_{A} < V_{B}$

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A spherical shell is cut into two pieces along a chord and separated by a large distance as shown in figure. For points A and B, where V and →E are gravitational potential and field respectively, then

The correct option is B VA<VB and |→EA|=|→EB|Since the net gravitational field inside a spherical shell is zero →EA+→EB=0 |→EA|=|→EB| Analyzing gravitational field lines, VA<VB

A spherical shell is cut into two pieces along a chord and separated by a large distance as shown in figure. For points $A$ and $B$ , where $V$ and $\to E$ are gravitational potential and field respectively, then

The correct option is B $V_{A} < V_{B} and | {\to E}_{A} | = | {\to E}_{B} |$
Since the net gravitational field inside a spherical shell is zero
${\to E}_{A} + {\to E}_{B} = 0$
$| {\to E}_{A} | = | {\to E}_{B} |$
Analyzing gravitational field lines, $V_{A} < V_{B}$