A spherical shell of radius $10 c m$ is carrying a charge $q$ . If the electric potential at distances $5 c m, 20 c m$ and $15 c m$ from the centre of the spherical shell is $V_{1}, V_{2}$ and $V_{3}$ respectively, then :

V_{1} > V_{2} > V_{3}

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V_{2} < V_{3} < V_{1}

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V_{1} = V_{2} > V_{3}

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V_{1} = V_{2} < V_{3}

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Solution

The correct option is D $V_{2} < V_{3} < V_{1}$
Radius of shell $r = 10 c m$
Potential at a point inside the spherical shell is same as that on its surface.
Thus potential at distance $5$ cm from center $V_{1} = \frac{k q}{r} = \frac{k q}{10}$
Potential at distance $20$ cm from center $V_{2} = \frac{k q}{20}$
Potential at distance $15$ cm from center $V_{3} = \frac{k q}{15}$
$⟹$ $V_{2} < V_{3} < V_{1}$

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A spherical shell of radius 10 cm is carrying a charge q. If the electric potential at distances 5 cm,20 cm and 15 cm from the centre of the spherical shell is V1,V2 and V3 respectively, then :

The correct option is D V2<V3<V1Radius of shell r=10cmPotential at a point inside the spherical shell is same as that on its surface.Thus potential at distance 5 cm from center V1=kqr=kq10 Potential at distance 20 cm from center V2=kq20Potential at distance 15 cm from center V3=kq15⟹ V2<V3<V1

A spherical shell of radius $10 c m$ is carrying a charge $q$ . If the electric potential at distances $5 c m, 20 c m$ and $15 c m$ from the centre of the spherical shell is $V_{1}, V_{2}$ and $V_{3}$ respectively, then :