A spherical shell of radius 10 cm is carrying a charge q. if the electric potential at distances 5 cm, 10 cm and 15 cm from the centre of the spherical shell is $V_{1}, V_{2} a n d V_{3}$ respectively, then

$V_{1} = V_{2} > V_{3}$

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$V_{1} > V_{2} > V_{3}$

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$V_{1} = V_{2} < V_{3}$

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$V_{1} < V_{2} < V_{3}$

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Solution

The correct option is A
$V_{1} = V_{2} > V_{3}$

Inside the spherical shell potential same

$V_{1} = V_{2}$

And outside the spherical shell

$V \propto \frac{1}{d} ∴ V_{1} = V_{2} > V_{3}$

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A spherical shell of radius 10 cm is carrying a charge q. if the electric potential at distances 5 cm, 10 cm and 15 cm from the centre of the spherical shell is V1,V2 and V3 respectively, then

The correct option is A V1=V2>V3 Inside the spherical shell potential same V1=V2 And outside the spherical shell V∝1d∴V1=V2>V3

A spherical shell of radius 10 cm is carrying a charge q. if the electric potential at distances 5 cm, 10 cm and 15 cm from the centre of the spherical shell is $V_{1}, V_{2} a n d V_{3}$ respectively, then

The correct option is A
$V_{1} = V_{2} > V_{3}$

Inside the spherical shell potential same

$V_{1} = V_{2}$

And outside the spherical shell

$V \propto \frac{1}{d} ∴ V_{1} = V_{2} > V_{3}$