Perimeter of semi−circle=πrP1=π(0.5)=π2 cmP2=π(1)=π cmP3=π(1.5)=3π2 cmP1,P2,P3 are the lengths of the semi−circles.π2,π,3π2,2π……P1=π2 cmP2=π cmd=P2−P1=π−π2=π2First term=P1=a=π2 cmSn=n2[2a+(n−1)d]Therefore, Sum of the length of 13 consecutive circles,S13=132[2(π2)+(13−1)π2]=132[π+6π]=132(7π)
= 132×7×227
= 143 cm