A spring of spring constant $240 N m^{- 1}$ is compressed by 10cm whereas another similar spring is extended by 10cm. The difference in the stored potential energies of two springs is

zero

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.2 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A zero
Both will store same P.E. so difference of P.E. will be zero.

Suggest Corrections

Similar questions

Out of a pair of identical springs of spring constants 240 N/m, one is compressed by 10 cm and other is stretched by 10 cm. The difference in P.E. stored in the two springs is:

Q. When a spring is stretched by

10 c m

, the potential energy stored is E. When the spring is stretched by

10 c m

more, the potential energy store in the spring becomes:

Q. A spring with spring constants K when compressed by 1 cm, the potential energy stored is U.If it is further compressed by 3 cm, then its final potential energy is

Q. Q. A spring with spring constant k when compressed by 1 cm, the potential energy stored is U. if it is further compressed by 3 cm then change in potential energy is
3U
9U
8U
15U

Q. When a ling spring is stretched by

2 c m

its potential energy is

U

. If the spring is stretched by

10 c m

, the potential energy stored in it will be

Join BYJU'S Learning Program

A spring of spring constant 240Nm−1 is compressed by 10cm whereas another similar spring is extended by 10cm. The difference in the stored potential energies of two springs is

The correct option is A zeroBoth will store same P.E. so difference of P.E. will be zero.

A spring of spring constant $240 N m^{- 1}$ is compressed by 10cm whereas another similar spring is extended by 10cm. The difference in the stored potential energies of two springs is

The correct option is A zero
Both will store same P.E. so difference of P.E. will be zero.