Question

A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of ${30}^o$ with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque experienced by the coil?

Answer 1

Magnitude of torque experienced by coil in the magnetic field is given by,

$\tau =nBIAsin\theta =0.96Nm$

where $A=l\times l$