A square floor of side $30 m$ is to be tiled with right triangles of side $3 m, 4 m$ and $5 m$ respectively .

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Solution

Area of floor $= 30 \times 30 = 900 m^{2}$
area of tile $= \frac{1}{2} \times 3 \times 4 = 6 m^{2}$
$∴$ No. of tiles required $= \frac{900}{6} = 150$

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A square floor of side 30 m is to be tiled with right triangles of side 3m,4m and 5m respectively .

Area of floor =30×30=900m2area of tile =12×3×4=6m2∴ No. of tiles required =9006=150

A square floor of side $30 m$ is to be tiled with right triangles of side $3 m, 4 m$ and $5 m$ respectively .

Area of floor $= 30 \times 30 = 900 m^{2}$
area of tile $= \frac{1}{2} \times 3 \times 4 = 6 m^{2}$
$∴$ No. of tiles required $= \frac{900}{6} = 150$