A square is inscribed in the circle $x^{2} + y^{2} - 2 x + 4 y + 3 = 0$ , whose sides sre parallel to the coordinate axes. One vertex of the square is

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$(2,2-\sqrt2)$

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Solution

The correct option is A

$Substitute given options in circle equation$

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The correct option is A Substitute given options in circle equation

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$Substitute given options in circle equation$