A square park has each side of $100 m$ . At each corner of the park, there is a flower bed in the form of a quadrant of radius $14 m$ as shown in figure. Find the area of the remaining part of the park. [Use $π = \frac{22}{7}$ ]

12843 m^{2}

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11284 m^{2}

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9384 m^{2}

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7382 m^{2}

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Solution

The correct option is C $9384 m^{2}$
Area of remaining park $=$ area of park $- 4$ $\times$ area of $1$ quadrant

$= {(100)}^{2} - 4 \times \frac{1}{4} \times π r^{2}$

$= 10000 -$ $\frac{22}{7} \times 14 \times 14$

$= 10000 - 616$

$= 9384$ $m^{2}$

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Question 2

A square shaped park ABCD of side 100 m has two equal rectangular flower beds each of size 10 m $\times$ 5 m (see the figure). Length of the boundary of the remaining park is

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A square park has each side of 100m. At each corner of the park, there is a flower bed in the form of a quadrant of radius 14m as shown in figure. Find the area of the remaining part of the park. [Use π=227]

The correct option is C 9384m2Area of remaining park = area of park −4×area of 1 quadrant =(100)2−4×14×πr2 =10000− 227×14×14 =10000−616 =9384 m2

A square park has each side of $100 m$ . At each corner of the park, there is a flower bed in the form of a quadrant of radius $14 m$ as shown in figure. Find the area of the remaining part of the park. [Use $π = \frac{22}{7}$ ]

The correct option is C $9384 m^{2}$
Area of remaining park $=$ area of park $- 4$ $\times$ area of $1$ quadrant

$= {(100)}^{2} - 4 \times \frac{1}{4} \times π r^{2}$

$= 10000 -$ $\frac{22}{7} \times 14 \times 14$

$= 10000 - 616$

$= 9384$ $m^{2}$