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Question

A square PQRS and an equilateral triangle XYZ are rearranged to form a figure as shown.

What is the perimeter of the ABDF ? (Take 2 = 1.4 and 3 = 1.7)


  1. 24.4


Solution

The correct option is A 24.4

To find the perimeter of ABDF, we need to know the following sides :

AB, BD, DF and AF

AB = XO (height of the equilateral XYZ) 

      = XY2YO2

      = 8242

      = 6416

      = 48 = 43 cm

BD = 8 cm (side of  equilateral XYZ)

DF = 4 cm (side of  square PQRS)

AF = Diagonal of square

      = PQ2+QR2

     = 42+42

    =  32 =  42 cm

Perimeter of ABDF = AB + BD + DF + AF

43 + 8 + 4 + 42

= 6.8 + 12 + 5.6

= 24.4 cm

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