Question

A square shape of park of area 23,104 sq. m is to be enclosed with wire placed at heights 1,2,3,4 m above the ground . Find required length of the wire ,if its length required for each circuit is 10% greater than the perimeter of the field

Answer 1

perimeter = $4\times$ side

Area of square park = $a^2=23104\Rightarrow a=152m$

$\therefore$ perimeter = $4\times 152m$

Length of each circle = $4\times 152\times \frac{110}{100}$

The wire goes arround 4 times, so total length of the wire required = $4\times 152\times \frac{110}{100}\times 4$

$=2675.2m$