A standard reduction electrode potentials of four metals are A = -0.250 V, B = -0.140 V, C = -0.126 V, D = -0.402V The metal that displaces A from its aqueous solution is:
A
B
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B
C
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C
D
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D
none of the above
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Solution
The correct option is A D Reduction potential of D is minimum i.e. −0.402V.Thus oxidation potential of D is maximum i.e. to +0.402V. D can oxidise itself and reduce other. The aqueous solution A will be present in its ionic form and can be reduced by D as its reduction potential is higher than D.