wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A standing wave is formed by the superposition of two travelling in opposite directions. The transverse displacement is given by
y(x,t)=0.5sin(5π4x)cos(200πt).
What is the speed of the travelling wave moving in the positive x direction?
(x and t are in meter and second, respectively.)

A
160m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
90m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
180m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
120m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 160m/s
The given equation is
y(x,t)=0.5sin(5π4x)cos(200πt)
y(x,t)=0.25×2sin(5πx/4)cos(200πt)
y(x,t)=0.25[sin(5πx/4+200πt)+sin(5πx/4200πt)]
From the above equation,
ω=200π
k=5π4
Velocity, v=ωk
v=200π5π/4=160m/s
The correct option is A.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Aftermath of SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon