Question

A started on my bicycle at $7$ $a.m.$ to reach a certain place. After going a certain distance his bicycle went out of order. Consequently, A rested for $35$ minutes and came back to his house walking all the way A reached my house at $1$ $p.m.$ If his cycling speed is $10$ $kmph$ and his walking speed is $1$ $kmph$, then on his bicycle A covered a distance of :

• A. $4\frac{61}{66}$ $km$
• B. $13\frac{4}{9}$ $km$
• C. $14\frac{3}{8}$ $km$
• D. $15\frac{10}{21}$ $km$

Answer 1

The correct option is A $4\frac{61}{66}$ $km$

Let the Distance Reached when Bicycle Went out of order be $10\times T$ where $T$ is the time taken to reach there

Now, Time taken by Walking $+$ Time for Resting $=6-\frac{35}{60}-T$

So, Distance Covered on Walking $=1\times (6-\frac{35}{60}-T)$

Now, Comparing The distances covered, we get

$10T=(\frac{325}{60}-T)$

$T=\frac{325}{660}$

Distance Covered by Bicycle $=10T=10\times \frac{325}{660}=4\frac{61}{66}$

Therefore Answer is $\left(A\right)$