1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A stationary body of mass m is slowly lowered onto a rough massive platform moving at a constant velocity v0=4 m/s. If the displacement of the body with respect to the platform (μ=0.2) is x m, then x is (Take g=10 m/s2)

A
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 4 With respect to platform, the initial velocity of the body of mass m is 4 m/s towards left (opposite to massive platform) and it starts retarding at the rate of a due to friction. So, a=fm=μmgm=μg a=0.2×10=2 m/s2 Using equation of motion, v2=u2+2as ⇒0=42+(2×−2×x) (∵a=−2 m/s2) ⇒x=4 m Hence, option (a) is correct.

Suggest Corrections
17
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program