You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Production

Material Removal Rate (MRR)

A steel bar 2...

Question

A steel bar $200 m m$ in a diameter is turned at a feed of $0.25 m m / r e v$ With a depth of cut of $4 m m$ The rotational speed of the workpiece is $160 r p m$ . The material removal rate in $m m^{3} / s$ is

160

No worries! We‘ve got your back. Try BYJU‘S free classes today!

167.6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1600

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1675.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $1675.5$
$M R R = f . d . v = f d \times \frac{π D N}{60}$
$= 0.25 \times 4 \times \frac{π \times 200 \times 160}{60} m m^{3} / s$
$= 1675.5 m m^{3} / s$

Suggest Corrections

Similar questions

Common Data:
A disc of $200 m m$ outer and $80 m m$ inner diameter is faced at a feed of $0.1 m m / r e v$ with a depth of cut of $1 m m$ . The facing operation is undertaken at a constant cutting speed of $90 m / m i n$ in a CNC lathe The main (tangential) cutting force is $200 N$

Neglecting the contribution of the feed force towards cutting power, the specific cutting energy in $J / m m^{3}$ is

Q. Common Data:
In orthogonal turning of a bar of

100 m m

diameter with a feed of

0.25 m m / r e v

, depth of cut of

4 m m

and cutting velocity of

90 m / m i n

, it is observed that the main (tangential) cutting force is perpendicular to the friction force acting at the chip-tool interface. The main (tangential) cutting force is

1500 N

.

The orthogonal rake angle of the cutting toll in degree is

Common Data:
In orthogonal turning of a bar of $100 m m$ diameter with a feed of $0.25 m m / r e v$ , depth of cut of $4 m m$ and cutting velocity of $90 m / m i n$ , it is observed that the main (tangential) cutting force is perpendicular to the friction force acting at the chip-tool interface. The main (tangential) cutting force is $1500 N$ .

The normal force acting the chip-tool interface in N is

Q. In orthogonal turning of medium carbon steel, the specific machining energy is

2. J / m m^{3}

. The cutting velocity, feed and depth of cut are

120 m / m i n, 0.2 m m / r e v

and

2 m m

respectively. The main cutting force in

N

Q. A specimen is being grinded on a surface grinder with grinding wheel speed of 1600 m/min, and workpiece speed of 25 mm/min, grinding wheel diameter of 200 mm, grinding depth of cut of 0.025 mm. Take transverse feed of workpiece = 4.4 mm/pass and specific cutting energy =

2200 J / m m^{3}

. Assume that pitch of grits at periphery of grinding wheel is 12 mm, the factor for negative rake angle of abrasive grains as 5. Mean grinding power in above operation will be___kW

Join BYJU'S Learning Program

A steel bar 200mm in a diameter is turned at a feed of 0.25mm/rev With a depth of cut of 4mm The rotational speed of the workpiece is 160rpm. The material removal rate in mm3/s is

The correct option is D 1675.5MRR=f.d.v=fd×πDN60 =0.25×4×π×200×16060mm3/s =1675.5mm3/s

A steel bar $200 m m$ in a diameter is turned at a feed of $0.25 m m / r e v$ With a depth of cut of $4 m m$ The rotational speed of the workpiece is $160 r p m$ . The material removal rate in $m m^{3} / s$ is

The correct option is D $1675.5$
$M R R = f . d . v = f d \times \frac{π D N}{60}$
$= 0.25 \times 4 \times \frac{π \times 200 \times 160}{60} m m^{3} / s$
$= 1675.5 m m^{3} / s$