The correct option is D 182 L
Applying the ideal gas equation,
n1=n2
P1V1RT1=P2V2RT2
Initial pressure P1=10 atm
Initial volume V1=20 L
Initial temperature T1=300 K
Final pressure P2=1 atm
Final temperature T2=273 K
Final volumeV2 is obtained as follows,
10×20R×300=1×V2R×273
⇒V2=182 L