A steel scale is to be prepared such that the millimeter intervals are to be accurate within 6-10-5 mm- The maximum temperature variation from the temperature of calibration during the reading of the millimeter marks is -12-10-6-C

A metre scale made of steel reads accurately at $20^{\circ} C$ . In a sensitive experiment, distances accurate up to 0.055 mm in 1 m are required. Find the range of temperature in which the experiment can be performed with this metre scale. Coefficient of linear expansion of steel $= 11 \times 10^{- 6}^{\circ} C^{- 1}$

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A steel scale is to be prepared such that the millimeter intervals are to be accurate within 6×10−5mm. The maximum temperature variation from the temperature of calibration during the reading of the millimeter marks is (α=12×10−6/∘C)

The correct option is C 5.0∘CThe change in length allowed for 1mm interval is 1mm×αΔθ=6×10−5mm So, Δθ=6×10−5/1.2×10−6=5oC

A steel scale is to be prepared such that the millimeter intervals are to be accurate within $6 \times 10^{- 5} m m$ . The maximum temperature variation from the temperature of calibration during the reading of the millimeter marks is $(α = 12 \times 10^{- 6} /^{\circ} C)$

The correct option is C ${5.0}^{\circ} C$
The change in length allowed for $1 m m$ interval is $1 m m \times α Δ θ = 6 \times 10^{- 5} m m$
So, $Δ θ = 6 \times 10^{- 5} / 1.2 \times 10^{- 6} = 5^{o} C$