A steel tank contains air at a pressure of 20 bar at 25⁰C . The tank is provided with a safety valve which can withstand a pressure of 40 bar.calculate the temperature to which the tank can be safely calculated

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Solution

Accoring to Gay Lussac law,

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} \frac{20}{298} = \frac{40}{?} T_{2} = \frac{298 \times 40}{20} = 596 K T_{2} = 596 - 273 = 323^{o} C$

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A steel tank contains air at a pressure of 20 bar at 250C . The tank is provided with a safety valve which can withstand a pressure of 40 bar.calculate the temperature to which the tank can be safely calculated

Accoring to Gay Lussac law, P1T1 =P2T2 20298 = 40?T2 = 298 × 4020 = 596 KT2 = 596 - 273 = 323 oC

A steel tank contains air at a pressure of 20 bar at 25⁰C . The tank is provided with a safety valve which can withstand a pressure of 40 bar.calculate the temperature to which the tank can be safely calculated

Accoring to Gay Lussac law,

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} \frac{20}{298} = \frac{40}{?} T_{2} = \frac{298 \times 40}{20} = 596 K T_{2} = 596 - 273 = 323^{o} C$