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Question

A steel tape is calibrated at 20C . when the temperature of the day is 10C , the percentage error in the measurement with the tape is (α=12×106/C)

A
3.6%
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B
0.36%
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C
0.18%
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D
0.036%
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Solution

The correct option is D 0.036%
We know,
l2=l1(1+αdt) where dt = change in temperature = 300 C
The percentage error in the measurement will be,
(dl/l) X100 = α dt 100 =12×30×100×106
=36×103 = 0.036%

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