A steel tape is calibrated at 20∘C . when the temperature of the day is −10∘C , the percentage error in the measurement with the tape is (α=12×10−6/∘C)
A
3.6%
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B
0.36%
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C
0.18%
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D
0.036%
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Solution
The correct option is D 0.036% We know, l2=l1(1+αdt) where dt = change in temperature = 300 C The percentage error in the measurement will be, (dl/l) X100 = α dt 100 =12×30×100×10−6 =36×10−3 = 0.036%