A steel wire of linear mass density $9.8 g / m$ is stretched with a tension of $10 k g$ . It is kept between poles of an electromagnet and it vibrates in resonance when carrying an arc of frequency $n$ . The frequency $n$ is

100 H z

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200 H z

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25 H z

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50 H z

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Solution

The correct option is C $50 H z$
Tension of string $T = m g = 98 N$
$μ = 9.8 \times 10^{- 3} k g / m$ , $l = 1 m$
now we know $f = \frac{1}{2 l} \sqrt{\frac{T}{μ}} = 50 H z$

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A steel wire of linear mass density 9.8 g/m is stretched with a tension of 10 kg. It is kept between poles of an electromagnet and it vibrates in resonance when carrying an arc of frequency n. The frequency n is

The correct option is C 50 HzTension of string T=mg=98Nμ=9.8×10−3kg/m ,l=1m now we know f=12l√Tμ=50Hz

A steel wire of linear mass density $9.8 g / m$ is stretched with a tension of $10 k g$ . It is kept between poles of an electromagnet and it vibrates in resonance when carrying an arc of frequency $n$ . The frequency $n$ is

The correct option is C $50 H z$
Tension of string $T = m g = 98 N$
$μ = 9.8 \times 10^{- 3} k g / m$ , $l = 1 m$
now we know $f = \frac{1}{2 l} \sqrt{\frac{T}{μ}} = 50 H z$