A step-up transformer operates at 200 volt line. The ratio of primary to secondary turns is 1:5. The output voltage in secondary coil is

0.1 V

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70 V

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1000 V

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2 V

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Solution

The correct option is C 1000 V
$\frac{N_{p r i m a r y}}{N_{s e c o n d a r y}} = \frac{V_{p r i m a r y}}{V_{s e c o n d a r y}}$
$\Rightarrow \frac{1}{5} = \frac{500}{V_{s}}$
$\Rightarrow V_{s} = 1000 V$

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The primary coil of a transformer contains 100 turns; the secondary has 200 turns. The primary coil is connected to a DC source that supplies a constant voltage of 1.5 volt. What is the voltage measured across the secondary coil?

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A step-up transformer operates at 200 volt line. The ratio of primary to secondary turns is 1:5. The output voltage in secondary coil is

The correct option is C 1000 VNprimaryNsecondary=VprimaryVsecondary ⇒15=500Vs ⇒Vs=1000V

The correct option is C 1000 V
$\frac{N_{p r i m a r y}}{N_{s e c o n d a r y}} = \frac{V_{p r i m a r y}}{V_{s e c o n d a r y}}$
$\Rightarrow \frac{1}{5} = \frac{500}{V_{s}}$
$\Rightarrow V_{s} = 1000 V$