A step-up transformer operators on a volt line and supplies a current of 2 A ,The ratio of primary and secondary winding is 1:5 The output voltage in the secondary is:

183.33 V

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40 V

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1000 V

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ZERO

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Solution

The correct option is B 183.33 V
$\begin{matrix} \frac{N_{P}}{N_{S}} = \frac{1}{5} \frac{N_{P}}{N_{S}} = \frac{V_{P}}{V_{S}} = \frac{1}{5} \frac{N_{P}}{N_{S}} = \frac{i_{s}}{i_{p}} = \frac{1}{5} = \frac{i_{s}}{2} i_{s} = \frac{5}{2} V_{S} = \frac{5}{6} \times 220 H e n c e, V_{S} = 183.33 V ∴ c o r r e c t o p t i o n i s A \end{matrix}$

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A step-up transformer operators on a volt line and supplies a current of 2 A ,The ratio of primary and secondary winding is 1:5 The output voltage in the secondary is:

The correct option is B 183.33 VNPNS=15NPNS=VPVS=15NPNS=isip=15=is2is=52VS=56×220Hence,VS=183.33V∴correctoptionisA