A step-up transformer operates on a 230 V line and supplies aload of 2 amp. The ratio of the primary and secondary windings is 1:25. The current in the primary is

15 A

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12.5 A

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25 A

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50 A

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Solution

The correct option is D 50 A
Current in the secondary coil $I_{s} = 2 A$
Given : $\frac{N_{p}}{N_{s}} = \frac{1}{25}$
Current in the primary coil $I_{p} = \frac{N_{s}}{N_{p}} I_{s} = 25 \times 2 = 50 A$
Correct answer is option D.

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A step-up transformer operates on a 230 V line and supplies aload of 2 amp. The ratio of the primary and secondary windings is 1:25. The current in the primary is

The correct option is D 50 ACurrent in the secondary coil Is=2 AGiven : NpNs=125Current in the primary coil Ip=NsNpIs=25×2=50 ACorrect answer is option D.

The correct option is D 50 A
Current in the secondary coil $I_{s} = 2 A$
Given : $\frac{N_{p}}{N_{s}} = \frac{1}{25}$
Current in the primary coil $I_{p} = \frac{N_{s}}{N_{p}} I_{s} = 25 \times 2 = 50 A$
Correct answer is option D.