In a step up transformer, the ratio of turns of primary to secondary is 1:10 and primary voltage is 230 V. If the load current is 2A, then current in the primary is

20A

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10A

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Solution

The correct option is A 20A
$\frac{N_{P}}{N_{S}} = \frac{1}{10}; \frac{V_{P}}{V_{S}} = \frac{N_{P}}{N_{S}}$
$\frac{230}{V_{S}} = \frac{1}{10}$
$V_{S} = 2300$
$V_{P} I_{P} = V_{S} I_{S}$
$I_{P} = \frac{V_{S} I_{S}}{V_{P}} = \frac{2300 \times 2}{230} = 20 A$

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In a step up transformer, the ratio of turns of primary to secondary is 1:10 and primary voltage is 230 V. If the load current is 2A, then current in the primary is

The correct option is A 20ANPNS=110;VPVS=NPNS 230VS=110 VS=2300 VPIP=VSIS IP=VSISVP=2300×2230=20A

The correct option is A 20A
$\frac{N_{P}}{N_{S}} = \frac{1}{10}; \frac{V_{P}}{V_{S}} = \frac{N_{P}}{N_{S}}$
$\frac{230}{V_{S}} = \frac{1}{10}$
$V_{S} = 2300$
$V_{P} I_{P} = V_{S} I_{S}$
$I_{P} = \frac{V_{S} I_{S}}{V_{P}} = \frac{2300 \times 2}{230} = 20 A$