Question

A stone dropped from the top of a tower reaches the ground with a velocity of 58.8 m/s in 6 seconds. Calculate the value of acceleration due to gravity.

• A. 10 m/s${}^2$
• B. 19.6 m/s${}^2$
• C. 8.2 m/s${}^2$
• D. 9.8 m/s${}^2$

Answer 1

Answer: (D)

9.8 m/s${}^2$

Here Initial velocity (u) = 0
Final velocity (v) = 58.8 m/s
Time (t) = 6 seconds
We know $v=u+at$
$58.8=a\times 6$
$\Rightarrow 6a=58.8$
$\Rightarrow a=\frac{58.8}{6}$
$\therefore a=9.8m/s^2$
$\therefore$ The value of acceleration due to gravity = 9.8 m/s${}^2$