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Question

# A stone falls freely under gravity. It covers distance h1,h2 and h3. In first 5 sec, next 5 sec and next 5 sec respectively. The relation between h1,h2 and h3 is

A
h1=h23=h35
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B
h2=3h1 and h3=3h2
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C
h1=h2=h3
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D
h1=2h2=3h3
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Solution

## The correct option is A h1=h23=h35For a particle released from a certain height the distance covered by the particle in relation with time is given by, h=12gt2For first 5 sec ,h1=12g(5)2=125Further next 5 sec h1+h2=h=12g(10)2=500⇒h2=375h1+h2+h3=12g(15)2=1125⇒h3=625So, h2=3h1h3=5h1or h1=h23=h35

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