Question

A stone is dropped freely from the top of a tower and it reaches the ground in 4 sec taking (g = $10m{s}^2$). Calculate the height of the Tower.

Answer 1

Given, $a=g=10m/s^2$

$t=4s$

$u=0m/s$ {Initial velocity at rest}

So, height= $ut+\frac{1}{2}a{t}^2$

$=\left(0\right)\left(u\right)+\frac{1}{2}\left(10\right)\left(16\right)$

$=80m$

$\therefore$ Height of the tower= $80m$ .